A 20-kg block starts from rest on a 36.87° frictionless incline as shown. The block is released, and its COG
drops 6 meters as the block slides to the bottom.
What is the block's GPE prior to being released?
b. What is the block's KE at the bottom?
What is the speed of the block on the frictionless
horizontal?
a.
C.

The answer is periosteum

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

The correct answer would be d. because when a volcanoe erupts it cobers the sun with thick ashes and blocks sunlight so there would beba big decrease in solar energy