A 40.9 kg satellite circles planet Cruton every 5.82 h. The magnitude of the gravitational force exerted on the satellite by Cruton is 105 N. (a) What is the radius of the orbit

r = 2.8524 x10⁷ m = 28524 km

Explanation:

First, we calculate the angular speed of the satellite:

Now, we use the formula for the gravitational force. Since gravitational force will be acting as the centrifugal force due to circular motion. Therefore,

where,

F = Gravitational Forc = 105 N

m = mass of satellite = 40.9 kg

v = linear speed of satellite = rω = r(3 x 10⁻⁴ rad/s)

r = radius of orbit = ?

Therefore,

r = 2.8524 x10⁷ m = 28524 km

divide the right side by the left side

0.024÷1.2=0.02 for example