A volleyball is spiked so that its incoming velocity of +2.63 m/s is changed to an outgoing velocity of -20.2 m/s. The mass of the volleyball is 0.350 kg. What is the magnitude of the impulse that the player applies to the ball?

The impuise is 7.9905 kg*m/s

Explanation:

Step one:

given data

v1= +2.63m/s

v2=-20.2m/s

mass m= 0.350kg

Step two:

From the expression for impulse

Ft= mΔv

substituting our data into the expression we have

Ft= 0.35*(-20.2-2.63)

Ft= 0.35*22.83

Ft=7.9905 kg*m/s

good looking response

k2s for potassium sulphide