You push on the top edge of a 1.8 m tall solid circular cylinder of iron which is 4.00 cm in diameter. You push with a horizontal force of 900 N to make the top of the pole flex to the right. Y = 10.0 x 1010 N/m2 B = 9.0 x 1010 N/m2 S = 4.0 x 1010 N/m2
How far does the top of the pole flex to the right?

Explanation:

From the question we are told that

Height of circular cylinder is

Diameter of cylinder

Horizontal Force  

Generally the formula for shear modulus is mathematically represented by

Where

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft