A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radial component of the acceleration (in m/s2) on the edge the wheel?

The radial component of the acceleration (in m/s2) on the edge the wheel is 369.45 m/s²

Using ω² = ω₀² + 2αθ, we find the final angular speed after 14 revolutions, ω where

So, substituting the values of the variables into the equation, we have

ω² = ω₀² + 2αθ,

ω² = (0 rad/s)² + 2 × 7 rad/s² × 87.965 rad.

ω² = 0 rad²/s² + 1231.504 rad²/s²

ω² = 1231.504 rad²/s²

ω = √(1231.504 rad²/s²)

ω = 35.09 rad/s

We know that the radial acceleration a = rω² where

So, substituting the values of the variables into the equation, we have

a = rω²

a = 0.30 m × (35.09 rad/s)²

a = 0.30 m × 1231.504 rad²/s²

a = 369.45 m/s²

So, the radial component of the acceleration (in m/s2) on the edge the wheel is 369.45 m/s².

Learn more about radial acceleration here:

link

Explanation:

Given that,

Initial angular velocity,

Acceleration of the wheel,

Rotation,

Let t is the time. Using second equation of kinematics can be calculated using time.

Let is the final angular velocity and a is the radial component of acceleration.

Radial component of acceleration,

So, the required acceleration on the edge of the wheel is .

igneous rocks also form where plates converge. the subducting plate melts as it sinks into the crust of the earth, and the melt rises into the overriding plate forming volcanoes. metamorphic rocks are formed mainly in the lithosphere, wherever there is high pressure and high temperature. -woods

answer( sicar );