Two charged particles attract each other with a force of magnitude F. If the distance between the charges is made 3.5 times as large and the charge on one of the particles is made 4 times as big, what is the ratio of the new F to the old one

The ratio between the forces is:

Explanation:

The electrostatic force equation is:

Where:

q1 and q2 are the electric charges

d is the distance between them

k is the electrostatic constant

Now, the distance is 3.5 times as large and q1 is 4 times as big, then the new force will be:

We can rewrite this equation in terms of F(old)

Therefore, the ratio between the forces is:

I hope it helps you!

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