A steady-state temperature difference of 85 K is impressed across a fiberglass layer of 13 cm thickness. The thermal conductivity of the fiberglass is 0.035 W/m K. Compute the heat transferred through the material per hour per meter squared.

21.54W/m²

Explanation:

Heat transferred through the material is expressed as;

Q =K∆T/∆x

Given

Thermal conductivity k = 0.035W/mK

∆T is the change in temperature = 80K

∆x is the thickness = 13cm = 0.13m

Substitute the given values into the formula

Q = 0.035(80)/0.13

Q = 2.8/0.13

Q = 21.54W/m²

Hence the heat transferred through the material is 21.54W/m²

double the distance = divide strength by 4