Two particles, an electron and a proton, are initially at rest in a uniform electric field of magnitude 480 N/C. If the particles are free to move, what are their speeds (in m/s) after 48.4 ns

Explanation:

Given;

electric field, E = 480 N/C

mass of electron, Me = 9.11 x 10⁻³¹ kg

mass of proton, Mp = 1.67 x 10⁻²⁷ kg

time of motion, t = 48.4 ns = 48.4 x 10⁻⁹ s

initial velocity of the particles, u = 0 (initially at rest)

let the speed of each particle after 48.4 ns = v

the magnitude of charge of the particles, q = 1.6 x 10⁻¹⁹ C

The force experienced by each particle is calculated as;

F = Eq

F = (480 N/C) x (1.6 x 10⁻¹⁹ C)

F = 7.68 x 10⁻¹⁷ N

The speed of each particle after 48.4 ns is calculated as;

where is the