Satellite a has an orbital radius 3.00 times greater than that of satellite
b. satellite b's orbital period around earth is 120 minutes. what is satellite a's orbital period?

Thank you for posting your question here at . Below is the solution:

To find the circumference (orbit) of an object, you use Pi x Diameter. 
As you have the circumference of B, you divide it by Pi to get the Diameter. 
So 120 divided by 3.141592654 = 38.2 minutes for the Diameter. 

As' radius and Diameter will be 3x greater than B. 
38.2 x 3 = 114.6 
To get back to the orbital period, times 114.6 by Pi, and you will get 360 minutes. 

Iwannasay c is the most accurate

The answer is  a.first and third quarters