Two copper spheres are currently 0.5 meters apart. One sphere has a charge of +3.4x10-4 C and the other has a charge of -5.6*10-4 C. What is the force between
the charged spheres? (k=8.89*10' Nm²/C2)
0 -6839.17 N
0 1200 N
0 5497.45 N
6839.17 N

6839.17 N

Explanation:

From the question given above, the following information were obtained:

Distance apart (r) = 0.5 m

Charge 1 (q₁) = +3.4×10¯⁴ C

Charge 2 (q₂) = -5.6×10¯⁴ C

Electrical constant (K) = 8.98×10⁹ Nm²/C²

Force (F) =.?

F = Kq₁q₂ / r²

F = 8.98×10⁹ × 3.4×10¯⁴ × 5.6×10¯⁴ / 0.5²

F = 1709.792 / 0.25

F = 6839.17 N

Thus, the force of attraction between the two charged spheres is 6839.17 N

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2