Acurrent of 9 a flows through an electric device with a resistance of 43 ohms. what must be the applied voltage in this particular circuit?

a. 387 v
b. 4.8 a
c. 387 a
d. 4.8 v

Use Ohm law

Voltage = (current) x (resistance). = ( 9 A ) x (43 ohms) = 387 volts.

Answer is A 387 V DO NOT make a mistake and check 387 A

i think the answer is a and b

i wish you luck

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures