Acat chases a mouse across a 1.2 m high table. the mouse steps out of the way, and the cat slides off the table and strikes the floor 1.3 m from the edge of the table.
what was the cat’s speed when it slid off the table? the acceleration of gravity is 9.81 m/s2 .
answer in units of m/s.

2.63 m/s

Explanation:

Step 1: identify the given parameters

height, H = 1.2 m

horizontal distance, d = 1.3 m

initial velocity, u = 0 m/s

acceleration due to gravity, = 9.81 m/s²

time, t = ?

the cat's speed, v = ?

Step 2: calculate the time it took the cat to reach a height of 1.2 m

Since u = 0, the equation reduces to;

, re-arrange this equation to obtain 't'

t = 0.495 s

Step 3: calculate the speed it took the cat to reach horizontal distance of 1.3m

d = v*t

v = d/t

v = 1.3/0.495

v = 2.63 m/s

answer: b.

explanation:

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!