Deuterium-Tritium Fusion Reaction
Given: energy released = 17.59 MeV per deuterium/tritium reaction pair (mass = 5 amu)
Equation: 2 1 H + 3 1 H -> 4 2 He + 1 0 n
Determine the energy released per kilogram of fuel used.
-Given MeV per reaction, calculate energy in joules per kilogram of reactants.
-Consider 1 mole of tritium plus 1 mole of deuterium to be a mole of "reactions" (total molar mass = 5 grams).
Answers: 3
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Deuterium-Tritium Fusion Reaction
Given: energy released = 17.59 MeV per deuterium/tritium reaction...
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