A horse is working steadily, providing 750 WW of output power. How much food energy does the horse need to work for 1 hour, to the nearest MJMJ

2.7MJ

Explanation:

Power is expressed according to the formula

Power = work done/Time

The energy required is also known as the work done

Given

Power = 750Watts

Time = 1hr = 3600secs

Substitute the given values into the formula

750 = work done/3600

Work done = 750×3600

Work done = 2,700,000Joules

Convert to megajoules

Since

1MJ = 10^6Joules

x = 2.7×10^6Joules

Cross multiply

10^6x = 2.7×10^6

x = 2.7×10^6/10^6

x = 2.7

Hence the amount of energy absorber by the food in MJ is 2.7MJ

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

f=ma newton's second law 7x8=56n