Periodic waves with a wavelength of 0.50 meter move with a speed of 0.30 meter in medium A. When the waves enter medium B, they travel at 0.15 meter per second. Calculate the wavelength of the waves in medium B.

0.25 m

Explanation:

Refraction occurs when the velocity or wavelength of a wave changes at the interface between two media.

We know that refractive index=

Wavelength in medium A/wavelength in medium B = velocity in medium A/velocity in medium B

Let the wavelength of medium B be a

0.5/a = 0.3/0.15

0.5 × 0.15 = 0.3 × a

a= 0.5 × 0.15/0.3

a= 0.25 m

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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if they have a finite resultant