PLZ HELP ME ITS MY LAST QUESTION I GOT LIKE 6 MIN LEFT A 77kg diver jumps from a 8.18m high diving platform. Why is the speed in m/s of the diver right before she hits the water?

12.7m/s

Explanation:

Given parameters:

Mass of the diver  = 77kg

Height  = 8.18m

Unknown:

Speed of the diver before hitting the water = ?

Solution:

The speed of the diver before hitting the water is the final velocity.

       To solve this problem, we use the expression below;

       v² = u²  + 2gH

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

H is the height

  Now insert the parameters and solve;

 v²   = 0²   + 2 x 9.8 x 8.18

 v²   = 160.328

  v  = 12.7m/s

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