12. How does the temperature of .033 kg of graphite change when it absorbs 350 J of thermal energy? (Graphite = 710 J/kgC)

14.94°C

Explanation:

Given parameters:

Mass of graphite  = 0.33kg

Quantity of heat absorbed  = 350J

Specific heat capacity of graphite = 710J/kg°C

Unknown:

Temperature change  = ?

Solution:

To solve this problem, we use;

        H  =  m c Ф  

H is the quantity of heat

m is the mass

c is the specific heat capacity

Ф is the change in temperature

       350  = 0.033 x 710 x Ф  

          Ф = 14.94°C