Two astronauts, A and B, both with mass of 60 kg, are moving along a straight line in the same direction in a "weightless" spaceship. Relative to the spaceship the speed of A is 2 m/s and that of B is 1 m/s. A is carrying a bag of mass 5 kg with him. To avoid collision with B, A throws the bag with a speed v relative to the spaceship towards B and B catches it. Find the minimum value of v. (1) 7.8 m/s
(2) 26.0 m/s
(3) 14.0 m/s
(4) 9.2 m/s

Explanation:

From the question we are told that

Mass of both astronauts

initial Speed of astronaut

initial Speed of astronaut

Mass of bag

Generally the initial momentum of astronaut  A+bag is mathematically given

as

Generally  for collision to be avoided astronauts have to move with steady pace of 1m/s or less,Because astronauts A final speed should be equal or less to that of B's.

Therefore

is the 3rd option making option 3(14m/s)correct.

answer; ///i believe that the correct answer is (45*) at a 45 degree check first good

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s