A wagon, initially traveling at a constant 8.2 m/s, starts going down a hill that creates an acceleration of 9.0 m/s2. What is the wagon's velocity 6.6 s after it starts accelerating down the hill?

67.6m/s

Explanation:

Given parameters:

Initial velocity  = 8.2m/s

Acceleration  = 9.0m/s²

Time  = 6.6s

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we use the expression below:

     Acceleration  =

v is the final velocity

u is the initial velocity

 t is the time taken

    9  =  

    v - 8.2  = 59.4

    v  = 59.4 + 8.2 = 67.6m/s

a 2,000 calorie based diet.

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.