From the well we take out a bucket of water with volume V=51m3 where aproximately the work done is A=450J. How deep is the surface of the well's water?
For velocity take g=10m/s2

9m

Explanation:

Given parameters:

Volume of the water  = 5liters;

 Since density = 1g/cm³  

         1L  = 1000cm³  

         5L  = 5000cm³

  So;

            mass  = density x volume  = 1 x 5000 = 5000g ; 5kg

Work done  = 450J

Acceleration due to gravity  = 10m/s²

Unknown:

Depth of the well  = ?

Solution:

To solve this problem;

 Work done  = mass x gravity x depth

 450 = 5 x 10 x depth

   depth  = 9m

spectral lines lyman is one set

c. newton's third law of motion