An aeroplane accelerates from rest to 65 m/s for take-off. It travels for 1200 m before take-off. What is its acceleration?

1.76m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 65m/s

Distance traveled  = 1200m

Unknown:

Acceleration  = ?

Solution:

This is linear velocity and we apply the appropriate motion equation to solve this problem.

      V²  = U² + 2as

S is the distance

u is the initial velocity

V is the final velocity

a is the acceleration

Now, insert the parameters and solve;

             65²  =  0² + 2 x a x 1200

             4225 = 2400a

                  a  = 1.76m/s²

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