A 1875 kg car going 23.0 m/s rear-ends a 1025 kg compact car going 17.0 m/s on ice in the same direction. The two cars lock together. How fast do the cars move together immediately after the collision?

The final velocity of both cars is 20.87 m/s.

Given that the two cars have a mass of 1875 kg and 1025 kg respectively and the velocity of both the cars is 23.0 m/s and 17.0 m/s.

The common velocity of both cars is given below.

Where v is the final velocity of both cars, m1 and m2 are the mass of both cars respectively. u1 and u2 are the initial velocities of both cars.

Substituting the values, we get the final velocity.

Hence we can conclude that the final velocity of both the cars is 20.87 m/s.

To know more about the velocity, follow the link given below.

link.

21 m/s

Explanation:

If

m1 = mass of 1875 kg car

u1 initial speed of 187 kg car = 23.0 m/s

m2 = mass of 1025 kg car

u2= initial speed of 1025 kg car = 17.0 m/s

Since they stuck together, they have a common final velocity v

From principle of conservation of linear momentum

m1u1 + m2u2 = (m1 + m2) v

v= m1u1 + m2u2/(m1 + m2)

v= 1875 × 23 + 1025× 17/(1875 + 1025)

v= 43125 + 17425/2900

v= 21 m/s

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explanation:

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