How much thermal energy is absorbed by 1.00X102 g of ice at -20.0°C to become
water at 0.0°C?

4202.4 J

Explanation:

The formula for calculating the heat absorbed by ice to melt into water is given by :

ΔH = Cp × m × Δ T   where ;

Cp =specific heat of ice = 2.06 J/g° C

m= mass of ice = 102 g

ΔT = 0°C--20°C = 20°C

Thermal energy absorbed by the ice will be;

ΔH = Cp × m × Δ T  

ΔH = 2.06 * 102 * 20

ΔH =4202.4 J

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