Two boys, shrijan having weight 600N and shrijesh having weight 300N are playing see-saw. If shrijan is sitting at 2m from fulcrum, where should shrijesh sit from fulcrum to balance shrijan? pl help me

Shrijesh should be located at 4[m] from the fulcrum point.

Explanation:

We must keep in mind that the moment around the point of rotation (fulcrum) must be equal, so that the bar remains in balance.

The moment for shrijan is:

So if the moment should be equal, the distance can be obtain from the same equation using the shrijesh's force or weight.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .