What is the net force acting on a box that is being pulled to the right with a 50 N force and to the left with a 10 N force? to the

We have that for the Question "What is the net force acting on a box that is being pulled to the right with a 50 N force and to the left with a 10 N force? to the " it can be said that The appropriate statement is

From the question we are told

What is the net force acting on a box that is being pulled to the right with a 50 N force and to the left with a 10 N force? to the

Generally the equation for the Net force  is mathematically given as

Fn=F_2-F_1

Therefore

Fn=F_2-F_1

Fn=50-10

Fn=40N

Therefore

The appropriate statement is

The net Force is 40N to the right

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Explanation:

A box that is pulled by 2 forces:

50N - 10N = 40N.

Since the force acting towards the right is stronger, there is a net force of 40N to the right and the box will move towards the right (if it has low static friction coefficient)

The answer is 40N to the right.

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).