A plane starting from rest accelerates to takeoff velocity of 75 m/s in 15
seconds. What was the plane’s
acceleration and how far did it travel
before takeoff?

The acceleration is 5 m/s² and the distance is 562.5  m.

Explanation:

Given that,

Initial velocity of the plane, u = 0 (at rest)

Final speed, v = 75 m/s

Time, t = 15 s

We need to find the acceleration of the plane and distance it travel before takeoff.

Let the distance is d.

So, the acceleration is 5 m/s² and the distance is 562.5  m.