A block slides along a frictionless surface and onto a slab with a rough surface. The slab has mass of 4 kg and the block has mass of 2 kg. What is the friction force on the small block at t = 1 second?

the friction force on the small block at t equals 1 second is 2N

Explanation:

Given the data in the question;

from the slope in the graph provided, we will get the acceleration of the slab

At t = 1 seconds

Slope = acceleration = ( 1 - 0) / ( 2 - 0 ) = 1/2 = 0.5 m/s²

Force = ma = 4 × 0.5 = 2 N

so by Newton's third law

Force on block will be same which is 2N

Therefore the friction force on the small block at t equals 1 second is 2N

the body's situation won't change the forces are equal opposit and on the same body

the answer is b i think