A tennis ball is hit with a speed of 30 m/s at an angle of 40 degrees above the horizontal. What is the range of the ball?

90.44 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 30 m/s

Angle of projection (θ) = 40°

Acceleration due to gravity (g) = 9.8 m/s²

Range (R) =?

The range of the ball can be obtained as follow:

R = u² Sine 2θ / g

R = 30² Sine (2×40) / 9.8

R = 900 Sine 80 / 9.8

R = 900 × 0.9848 / 9.8

R = 886.32 / 9.8

R = 90.44 m

Therefore, the range of the tennis ball is 90.44 m

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge