A car accidentally rolls off cliff as it leaves the cliff it has a horizontal velocity of 13 m/s it hits the ground 60 m from the shoreline calculate the height of the cliff

The height of the cliff from which the car rolls off is 104.59 m

We'll begin by calculating the the time taken for the car to reach the ground.

Horizontal distance (s) = 60 m

Horizontal velocity (u) = 13 m/s

t = 4.62 s

Thus, the time taken for the car to reach the ground is 4.62 s

Time (t) = 4.62 s

Acceleration due to gravity (g) = 9.8 m/s²

h = ½gt²

h = ½ × 9.8 × 4.62²

Therefore, the height of the cliff is 104.59 m

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h = 104.13 m

Explanation:

Given that,

Horizontal velocity of the car, v = 13 m/s

It hits the ground 60 m from the shoreline

We need to find the height of the cliff. Let t be the time of fall. We can find it as follows :

So, the time of fall is 4.61 seconds.

Let h is the height of the cilff. Using second equation of motion to find it as follows :

So, the height of the cliff is 104.13 m.

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2