I'll give brainliest . a train starts from rest and moves with a uniform acceleration of x metre per second square for 5 minutes determine the value of x if it covers a distance of 5.8 km during the journey

x = ~0.1289 m/s^2

Explanation:

We can use one of the kinematic formulas. We see that the equation doesn’t contain the final velocity, so we use the kinematic equation d = v_0t + (1/2)at^2.

Since the train started from rest, the initial velocity, v_0, is 0. Thus, the equation becomes:

d = (1/2)at^2

Note that 5 minutes is 300 seconds and 5.8 km is 5800 m. Substituting the values we are given, we get:

5800 m = (1/2)(x m/s^2)(300 s)^2 = (45000 s^2)(x m/s^2)

Dividing by 45,000 on both sides, we get:

x = ~0.1289 m/s^2

I hope this helps! :)

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