An airplane is flying at an elevation of 6 miles on a flight path that will take it directly over a radar tracking station. Let S represent the distance between the radar station and the plane. If S is decreasing at a rate of 400 mph when S is 10 miles, what is the velocity of the plane

Explanation:

h = Height at which the plane is flying = 6 miles

S = Distance between plane and radar = 10 miles

= Rate at which S is decreasing = -400 mph

Distance between S and and the elevation of the plane

From Pythagoras theorem we get

Differentiating with respect to time we get

Velocity of the plane is .

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

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