A bus starts to move from rest. If it is accelerated by 0.8m/s2, calculate the velocity and distance traveled after 8 s.

We are given:

Initial velocity (u) = 0 m/s

acceleration (a) = 0.8 m/s²

time interval (t) = 8 seconds

final velocity (v) = v m/s

distance travelled (s) = s m

Solving for the final velocity:

We know that:

v = u + at                                [first equation of motion]

v = 0 + (0.8)(8)                       [replacing the variables]

v = 6.4 m/s

Hence, the final velocity is 6.4 m/s

Solving for the distance travelled:

We know that:

s = ut + 1/2(at²)                     [second equation of motion]

s = (0)(8) + 1/2(0.8)(8)(8)      [replacing the variables]

s = 1/2(6.4*8)

s = 25.6 m

Hence, the distance travelled is 25.6 m

all of the answers are correct.

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explanation:

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