Problem 7:esvoe71017425b601f756a59bc7b76d2f 39502730941492c25f1dd66c7ed01e4bb38 ceovse 0N86-C1-52-40-A837-22820 If object A is twice the mass of object B what can be said about their kinetic energies just as they hit the ground

the kinetic energy of A will be twice that of B

Explanation:

The formula for calculating kinetic energy is expressed using the formula

KE = 1/2mv²

m is the mass of the object

v is the velocity

For object A:

KEA = 1/2mAvA²

For object B:

KEB = 1/2mBvB² ... 1

If object A is twice the mass of object B, then mA = 2mB

From 1:

KEA = 1/2mAvA²

Substitute mA = 2mB

KEA = 1/2(2mB)vA² 2

Divide 1 by 2

KEB/KEA = 1/2mBvB²/mBvA²

KEB/KEA = 1/2vB²/vA²

Assuming they have the same velocities then vA ,= VB

The equation becomes:

KEB/KEA = 1/2vB²/vA²

KEB/KEA = 1/2vB²/vB²

KEB/KEA = 1/2

KEA = 2EB

Hence the kinetic energy of A will be twice that of B

gets less

trig 15.3 cos