Unpolarized light with intensity 300 W/m^2 passes first through a polarizing filter with its axis vertical, then through a second polarizing filter. It emerges from the second filter with intensity 121 W/m^2. What is the angle from vertical of the axis of the second polarizing filter?

The angle from vertical of the axis of the second polarizing filter is 50.57⁰.

Explanation:

Given;

intensity of the unpolarized light, I₀ = 300 W/m²

intensity of emergent polarized light, I = 121 W/m²

let the angle from vertical of the axis of the second polarizing filter = θ

Apply Malus's law, intensity of emergent polarized light is given as;

I = I₀Cos²θ

Therefore, the angle from vertical of the axis of the second polarizing filter is 50.57⁰.

50 inches should be the resultant vector

the ima (higher than 1m) will be greater than the ima with the height of 1m.