A chimpanzee climbs a vine up and to the right for a total displacement of 50 m 50m50, start text, m, end text that makes a 60 ° 60°60, degree angle from the ground. What was the horizontal displacement of the chimpanzee in m mstart text, m, end text?

25m

Explanation

Let the horizontal displacement formula be expressed as;

Dx = Dcos theta

theta is the angles subtended by the displacement

Given

D = 50m

theta = 60°

Required

horizontal displacement of the chimpanzee

Substitute into the formula

Recall that: Dx = Dcos theta

Dx = 50cos60°

Dx = 50(0.5)

Dx = 25m

Hence the horizontal displacement of the chimpanzee is 25m

the area between the graph and the t axis

it is a negative acceleration