g A cylinder of length 2.75 m, radius 0.420 m, and mass 14.7 kg is rotated at an angular speed of 3.70 rad/s around an axis parallel to the length of the cylinder and through its center. Find the magnitude of the cylinder's angular momentum.

4.792 kgm²/s

Explanation:

Given that

Length of the cylinder, l = 2.75 m

Radius of the cylinder, r = 0.42 m

Mass of the cylinder, m = 14.7 kg

Angular speed of rotation, v = 3.7 rad/s

The magnitude of a cylinders angular momentum is given by the formula

L = I * v, where

I = moment of inertia about the axis given by mr²/2

I = (14.7 * 0.42²) / 2

I = 2.59 / 2

I = 1.295 kgm

L = I * v

L = 1.295 * 3.7

L = 4.792 kgm²/s

Therefore, the angular momentum of the cylinder is 4.792 kgm²/s

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards