A horizontal force of 92.7 N is applied to a 40.5 kg crate on a rough, level surface. If the crate accelerates at 1.13 m/s2, what is the magnitude of the force of kinetic friction (in N) acting on the crate

The value is

Explanation:

From the question we are told that

    The  magnitude of the horizontal force is

     The mass of the crate is  

     The acceleration of the crate is  

Generally the net force acting on the crate is mathematically represented as

Here is force of kinetic friction (in N) acting on the crate

      So  

=>        

1/0.14nm = 10^10/1.4 a lot

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