g A rock is thrown downward from the top of a 38.4-m-tall tower with an initial speed of 16 m/s. Assuming negligible air resistance, what is the speed of the rock just before hitting the ground

Final velocity, V = 31.76m/s

Explanation:

Given the following data;

Initial velocity = 16m/s

Distance = 38.4m

We know that acceleration due to gravity is equal to 9.8m/s².

To find the final velocity, we would use the third equation of motion;

Where;

Substituting into the equation, we have;

Taking the square root, we have;

Final velocity, V = 31.76m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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