a golf ball has a mass 0.046 kkg rests on a tee it is struck by a golf club with an effectiv mass of 0.22 and speed of 44 assuming the collision is elastic, find the speed of the ball when it leaves the tee

210 m/s

Explanation:

We will use this equation for an elastic collision:

In this case, m₁ = mass of golf ball (0.046 kg) and m₂ = mass of the golf club (0.22 kg).

v₁ is 0 m/s since the ball is at rest on the tee.

v₂ is 44 m/s, given in the problem.

v₁ is what we are trying to find.

v₂ is 0 m/s since the ball will be at rest on the ground.

Plug these values into the elastic collision equation:

Simplify this equation.

Get rid of the units.

Multiply the left side of the equation.

Divide both sides by 0.046.

The speed of the ball when it leaves the tee is about 210 m/s.

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the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.