A baseball is thrown upward at 20m/s. At what time is the ball 10m above the point at which it was released?

0.583 seconds

Explanation:

We are dealing with free-fall motion, which has a constant acceleration of -g, acceleration due to gravity, so we can use a constant acceleration equation to solve this problem.

List out known variables and the variable that we want to solve for:

Find the kinematic equation that contains all four of these variables:

Plug known values into the equation.

Distribute 1/2 inside the parentheses.

Set the equation equal to 0 and rearrange the terms so they are in descending degree order.

Factor this equation by using the quadratic formula. You should get:

Let's look at these numbers within the context of the problem. If the ball's speed is 20 m/s, then after 1 second, it would reach a height of 20 m.

However, we want to find the time that it would take the ball to reach a height of 10 m, which is half of 20 m. Therefore, the time to reach 10 m should be around 0.5 seconds.

t = 0.583 is the closest to 0.5 seconds, and it fits within the context of the problem. Therefore, the answer is 0.583 seconds.

. west

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