A student kicks a ball of 1 kg with a velocity of 13ms. The contact is 0.2 sec. Find the force

65 N

Explanation:

Assuming that the ball was at rest hence initial momentum = 0

Final momentum = mv = 1Kg × 13 ms-1 = 13 kgms-1

But

Ft= mv according to Newton's law

F= mv/t

F= 13kgms-1/0.2s

F= 65 N

65 N

Explanation:

Given that :

Mass of ball = 1kg

Velocity = 13m/s

Time = 2 seconds

Using the relation :

Force = (mass * change in velocity) / time

The change in momentum of the ball :

Momentum = mass * change in velocity

Velocity change = (13 - 0) ; Given that initial velocity = 0 (at rest)

Momentum = 1kg * 13m/s

Momentum = 13 kgm/s

Therefore, the force, F equals;

F = change in momentum / time

F = 13kgm/s ÷ 0.2 s

Hence, Force, F = 65N

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

the answer would be a