After a recent snow storm, you decide to sled down a hill in Fairmount Park. You take a running start and hit the slope with an initial velocity of 4.9 m/s. You then begin to accelerate at
4.2 m/s
2
for 4.7 seconds. How many meters will you travel in that time?

Here's what you need to know below:

69.42 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (vᵢ ) = 4.9 m/s

Acceleration (a) = 4.2 m/s²

Time (t) = 4.7 s

Displacement (Δx) =?

Thus, we can obtain the displacement by using the following formula:

Δx = vᵢt + ½at²

Δx = (4.9 × 4.7) + (½ × 4.2 × 4.7²)

Δx = 23.03 + (2.1 × 22.09)

Δx = 23.03 + 46.389

Δx = 69.419 ≈ 69.42 m

Thus, the distance travelled is 69.42 m

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow