A merry-go-round on a playground consists of a horizontal solid disk with a weight of 805 N and a radius of 1.58 m. A child applies a force 49.5 N tangentially to the edge of the disk to start it from rest. What is the kinetic energy of the merry-go-round disk (in J) after 2.95 s?

The value is

Explanation:

From the question we are told that

     The weight of the horizontal solid disk is  

      The radius of the horizontal solid disk is  

      The force applied by the child is  

       The time considered is  

Generally the mass of the  horizontal solid disk is mathematically represented as

=>      

=>      

Generally the moment of inertia  of the horizontal solid disk is mathematically represented as  

=>        

=>      

Generally the net torque experienced by the horizontal solid disk is mathematically represented as

=>        

=>        

=>        

Gnerally from kinematic equation we have that

Here   is the initial angular velocity velocity of the horizontal solid disk  which is  

So

=>        

Generally the kinetic energy is mathematically represented as

=>      

=>      

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer