A ball is thrown vertically upward with an initial velocity of 25 m/s. What is its velocity after 3 seconds in the air? (assume air resistance is negligible)

v = -5 m/s

Explanation:

It is given that,

The initial velocity of the ball, u = 25 m/s

We need to find its velocity after 2 seconds in the air.

Let v is the velocity of the ball after 2 seconds. Using equation of motion to find it.

v = u + at

Here, a = -g

v = u -gt

Putting all the values,

v = 25 - (10)(3)

= 25-30

= -5 m/s

So, the velocity of the ball after 3 seconds is 5 m/s and it is in downward direction.