An object has an average acceleration of + 6.24 m/s ^ 2 for 0.300 s . At the end of this time the object's velocity is + 9.31 m/s . What was the object's initial velocity?

initial velocity = 7.44 m/s   (3 s.f.)

Explanation:

a = 6.24 m/s²     t = 0.300 s     v = 9.31 m/s       u = ?

                               v = u + at

                       9.31 = u + (6.24 x 0.300)

                             9.31 = u + 1.872

                                    u = 7.438

                                    = 7.44 m/s       (3 s.f.)

Hope this helps!

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

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