Arace car travels a circular track at an average rate of 135 mi/hr. the radius of the track is 0.450 miles. what is the centripetal acceleration of the car?

Answer : .

Explanation :

It is given that,

Velocity of a race car, v = 135 mi/hr

Radius of the track, r = 0.45 miles

We know that the centripetal acceleration is defined as :

r is the radius of the circle.

So, the centripetal acceleration of the car is .

Hence, this is the required solution.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

a=d/t

a="triangle"v/t

explanation:

a = acceleration