A 0.50-kg ball is thrown vertically upward with an initial velocity of 35 m/s. Approximately, how high will the ball rise?

62.5m

Explanation:

Given parameters:

Mass of the ball  = 0.5kg

Initial velocity  = 35m/s

At the maximum height final velocity is 0m/s

Unknown:

Height of the rise of the ball = ?

Solution:

To solve this problem, we apply the right motion equation which is shown below;

           v²  = u² - 2gh

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

h is the height

Now insert the parameters and solve;

          0² = 35² - 2(9.8)(h)

      -1225 = -19.6h

           h = 62.5m

i would think it's food chain

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i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!