a car traveling at 28.4 m/s undergoes a constant deceleration of 1.92 m/s2 when the breaks are applied. How many revolutions does each tire make before the car comes to a stop

Complete Question

a car traveling at 28.4 m/s undergoes a constant deceleration of 1.92 m/s2 when the breaks are applied. How many revolutions does each tire make before the car comes to a stop? Assume that the car does not skid and that each tire has a radius of 0.307 m. Answer in units of rev.

The value is        

Explanation:

From the question we are told that

    The speed of the car is  

     The constant deceleration experienced is  

      The radius of the tire is  

Generally from kinematic equation we have that

Here  v is the final velocity which is  0 m/s

   So

=>      

Generally the circumference of the tire is mathematically represented as

=>          

=>      

Generally the number of revolution is mathematically represented as

=>    

=>          

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