You have a 100 N object with a normal force of 100 N. You apply a 50 N push to the right, but a friend is hiding on the other side of the object and is also pushing with a force of 60 N. What is the net force on the object?

100.49N

Explanation:

First we must know that the normal force acts in the vertical direction;

The force required to push to the right and left acts in the horizontal direction;

Sum of force along the horizontal Fx = 50N - 60 N = -10N

Force along the vertical Fy = 100N

The net force on the object is calculated as;

F = √(Fx)² + (Fy)²

F = √(-10)² + (100)²

F = √100 + 10000

F = √10,100

F = 100.49N

Hence the net force on the object is 100.49N

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