An elevator car with mass 300 kg accelerates up at 2.9 m/s/s. What is the Tension Force in the cable lifting the elevator car?

use g = 10 m/s/s

Answer to whole number.

the answer is d. 4

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the diagram which shows forces as either balanced = same speed or unbalanced = accelerarting

c) up

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electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j